Many different genes are involved in the production of pigments in mammals. One example is the TYR gene. Fur colour in rabbits involves a number of different genes. Some of these genes interact. Gene 1 has two alleles, $$\(\mathbf{B}\)$$ and $$\(\mathbf{b}\)$$. - The dominant allele, B, results in black fur. - The recessive allele, $$\(\mathbf{b}\)$$, results in brown fur. Gene 2 has two alleles, $$\(F\)$$ and $$\(\mathbf{f}\)$$. - The dominant allele, $$\(\mathbf{F}\)$$, codes for a protein that allows the expression of gene 1. - The recessive allele, $$\(\mathbf{f}\)$$, codes for a protein that does not allow the expression of gene 1 , resulting in white fur. The two genes are on different pairs of autosomes. Complete the genetic diagram for a cross between two black rabbits that are heterozygous for both genes and show the ratio of possible offspring phenotypes. parental phenotypes black $$\(\times\)$$ black parental genotypes BbFf $$\(\times\)$$ BbFf Punnett square ratio of offspring phenotypes: .........................................................................................................................................

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