A cup of coffee at temperature $$\(180^{\circ} \mathrm{F}\)$$ is placed on a table in a room at $$\(68^{\circ} \mathrm{F}\)$$. The d.e. for its temperature at time $$\(t\)$$ (in minutes) is $$\(\frac{d y}{d t}=-0.11(y-68) ; y(0)=180\)$$. After 10 minutes, the temperature (in $$\({ }^{\circ} \mathrm{F}\)$$ ) of the coffee is approximately

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