A block of lead measuring $$\(10 \mathrm{~cm} \times 10 \mathrm{~cm} \times 10 \mathrm{~cm}\)$$ contains $$\(3.295 \times 10^{25}\)$$ atoms. Calculate the density of lead. [ $$\(A_{\mathrm{r}}\)$$ value: $$\(\mathrm{Pb}=207.2\)$$ Avogadro constant, $$\(L=6.02 \times 10^{23} \mathrm{~mol}^{-1}\)$$ ]
A.
\(3.79 \mathrm{~g} \mathrm{~cm}^{-3}\)
B.
\(\quad 4.49 \mathrm{~g} \mathrm{~cm}^{-3}\)
C.
\(11.34 \mathrm{~g} \mathrm{~cm}^{-3}\)
D.
\(54.73 \mathrm{~g} \mathrm{~cm}^{-3}\)
Exam No：wch11-01-que-20240111 Year：2024 Question No：8
Answer:
C
Knowledge points:
1.Formulae, Equations and Amount of Substance
Solution:
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