A 1.00-mole sample of \(\ce{CH3OH}\) is placed in container B and the system is allowed to go to equilibrium. What can be said about the relative rates of reaction with respect to the various components?
A.
The rate of CO formation is numerically equal to the rate of \(\ce{CH3OH}\) loss.
B.
The rate of \(\ce{H2}\) (g) formation is numerically equal to the rate of \(\ce{CH3OH}\) loss.
C.
The rate of \(\ce{H2}\) (g) formation is half the rate of CO(g) formation.
D.
The rate of \(\ce{H2}\) (g) formation is equal to the rate of CO(g) formation.
Exam No：AP Chemistry Problem Set 7 Year：2024 Question No：APChemistry2024AP0215
Answer:
A
Knowledge points:
7.7 Calculating Equilibrium Concentrations
Solution:
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