Another compound of chromium has the formula $$\(\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{C}_{10} \mathrm{O}_{10}\)$$. Complete Table 5.1 to calculate the relative molecular mass of $$\(\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{C}_{10} \mathrm{O}_{10}\)$$. relative molecular mass $$\(=\)$$ ..........................

Chemistry
IGCSE&ALevel
CAIE
Exam No:0620_s24_qp_31 Year:2024 Question No:5(d)

Answer:



Knowledge points:

3.3.1. State that concentration
3.3.2. State that the mole, mol, is the unit of amount of substance
3.3.3.1. amount of substance
3.3.3.2. mass
3.3.3.3. molar mass
3.3.3.4. relative atomic mass or relative molecular / formula mass
3.3.3.5. number of particles, using the value of the Avogadro constant
3.3.4. Use the molar gas volume, taken as 24 dm3 at room temperature and pressure, r.t.p., in calculations involving gases
3.3.5. Calculate stoichiometric
3.3.6. Use experimental data from a titration to calculate the moles of solute, or the concentration or volume of a solution
3.3.7. Calculate empirical formulae and molecular formulae, given appropriate data
3.3.8. Calculate percentage yield, percentage composition by mass and percentage purity, given appropriate data

Solution:

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