Chlorine is one of the elements in Group 17 of the Periodic Table. The halogenoalkane $$\(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Cl}\)$$ forms when chlorine reacts with $$\(\mathrm{C}_{2} \mathrm{H}_{6}\)$$ via a free-radical substitution mechanism. (i) Define free radical. ....................................................................................................................................... . ................................................................................................................................. (ii) State the essential condition for chlorine to react with $$\(\mathrm{C}_{2} \mathrm{H}_{6}\)$$ at room temperature. ................................................................................................................................. (iii) Write two equations to show the propagation steps in this reaction. 1 .................................................................................................................................... 2 ....................................................................................................................................
Exam No:9701_w24_qp_23 Year:2024 Question No:2(b)
Answer:

Knowledge points:
11.4.1 describe and interpret, in terms of changes in oxidation number, the reaction of chlorine with cold and with hot aqueous sodium hydroxide and recognise these as disproportionation reactions
11.4.2 explain, including by use of an equation, the use of chlorine in water purification to include the production of the active species HOCl and which kill bacteria.
Solution:
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