Chlorine is one of the elements in Group 17 of the Periodic Table. The halogenoalkane $$\(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Cl}\)$$ forms when chlorine reacts with $$\(\mathrm{C}_{2} \mathrm{H}_{6}\)$$ via a free-radical substitution mechanism. (i) Define free radical. ....................................................................................................................................... . ................................................................................................................................. (ii) State the essential condition for chlorine to react with $$\(\mathrm{C}_{2} \mathrm{H}_{6}\)$$ at room temperature. ................................................................................................................................. (iii) Write two equations to show the propagation steps in this reaction. 1 .................................................................................................................................... 2 ....................................................................................................................................

Chemistry
IGCSE&ALevel
CAIE
Exam No:9701_w24_qp_21 Year:2024 Question No:2(b)

Answer:



Knowledge points:

6.1.1 calculate oxidation numbers of elements in compounds and ions
6.1.2 use changes in oxidation numbers to help balance chemical equations
6.1.3 explain and use the terms redox, oxidation, reduction and disproportionation in terms of electron transfer and changes in oxidation number
6.1.4 explain and use the terms oxidising agent and reducing agent
6.1.5 use a Roman numeral to indicate the magnitude of the oxidation number of an element

Solution:

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