Compounds $$\(\mathbf{A}, \mathbf{B}, \mathbf{C}\)$$ and $$\(\mathbf{D}\)$$ all have the molecular formula $$\(\mathrm{C}_{4} \mathrm{H}_{8}\)$$. $$\(\mathbf{A}, \mathbf{B}\)$$ and $$\(\mathbf{C}\)$$ each contain one double bond, but $$\(\mathbf{D}\)$$ does not. $$\(\mathbf{A}\)$$ and $$\(\mathbf{B}\)$$ are geometric isomers of each other. The carbon-carbon double bond consists of a $$\(\sigma\)$$ bond and a $$\(\pi\)$$ bond. Describe the difference between the $$\(\sigma\)$$ bond and the $$\(\pi\)$$ bond. Include a labelled diagram in your answer. (4) ................................................................................................................................................................................................................................................................................ ................................................................................................................................................................................................................................................................................ ................................................................................................................................................................................................................................................................................ ................................................................................................................................................................................................................................................................................ ................................................................................................................................................................................................................................................................................

Chemistry
IGCSE&ALevel
EDEXCEL
Exam No:wch11-01-que-20240111 Year:2024 Question No:18

Answer:





Knowledge points:

5.Alkenes

Solution:

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