There is a galvanic cell involving a lead, Pb, electrode in a 1.0 M lead(II) nitrate, \(\ce{Pb(NO3)2}\) , solution and a chromium, Cr, electrode in a 1.0 M chromium(II) sulfate, CrSO4 , solution. What is the cell potential?
A.
+0.78 V
B.
-0.78 V
C.
+1.04 V
D.
0.00 V
Exam No：AP Chemistry Problem Set 7 Year：2024 Question No：APChemistry2024AP0221
Answer:
A
Knowledge points:
9.8 Galvanic (Voltaic) and Electrolytic Cells
Solution:
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