A car of mass $$\(1400 \mathrm{~kg}\)$$ is moving on a straight road against a constant force of $$\(1250 \mathrm{~N}\)$$ resisting the motion. The car now travels at a constant speed of $$\(32 \mathrm{~m} \mathrm{~s}^{-1}\)$$ up a section of the road inclined at $$\(\theta^{\circ}\)$$ to the horizontal, with the engine working at $$\(64 \mathrm{~kW}\)$$. Find the value of $$\(\theta\)$$. .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... ....................................................................................................................................................
Exam No:9709_w21_qp_43 Year:2021 Question No:4(b)
Answer:
\(\frac{64000}{32}=1250+1400 g \sin \theta\)
\(\theta=3.1[3.0708 \ldots]\)
\(\theta=3.1[3.0708 \ldots]\)
Knowledge points:
4.1.2 understand the vector nature of force, and find and use components and resultants; Calculations are always required, not approximate solutions by scale drawing.
4.1.3 use the principle that, when a particle is in equilibrium, the vector sum of the forces acting is zero, or equivalently, that the sum of the components in any direction is zero (Solutions by resolving are usually expected, but equivalent methods (e.g. triangle of forces, Lami’s Theorem, where suitable) are also acceptable; these other methods are not required knowledge, and will not be referred to in questions.)
4.5.4 use the definition of power as the rate at which a force does work, and use the relationship between power, force and velocity for a force acting in the direction of motion Including calculation of (average) power;P = Fv
Solution:
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