A car starts from rest and moves in a straight line with constant acceleration $$\(a \mathrm{~m} \mathrm{~s}^{-2}\)$$ for a distance of $$\(50 \mathrm{~m}\)$$. The car then travels with constant velocity for $$\(500 \mathrm{~m}\)$$ for a period of $$\(25 \mathrm{~s}\)$$, before decelerating to rest. The magnitude of this deceleration is $$\(2 a \mathrm{~m} \mathrm{~s}^{-2}\)$$. Find the value of $$\(a\)$$. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................
Exam No:9709_s20_qp_43 Year:2020 Question No:4(b)
Answer:
Constant velocity \(=500 / 25=20 \mathrm{~ms}^{-1}\)
$
20^{2}=0+2 a \times 50
$
\(a=4\)
$
20^{2}=0+2 a \times 50
$
\(a=4\)
Knowledge points:
4.2.2.1 the area under a velocity–time graph represents displacement
4.2.2.2 the gradient of a displacement–time graph represents velocity
4.2.2.3 the gradient of a velocity–time graph represents acceleration
Solution:
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