A child of mass $$\(35 \mathrm{~kg}\)$$ is swinging on a rope. The child is modelled as a particle $$\(P\)$$ and the rope is modelled as a light inextensible string of length $$\(4 \mathrm{~m}\)$$. Initially $$\(P\)$$ is held at an angle of $$\(45^{\circ}\)$$ to the vertical (see diagram). Given that there is no resistance force, find the speed of $$\(P\)$$ when it has travelled half way along the circular arc from its initial position to its lowest point. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................
Exam No:9709_s20_qp_41 Year:2020 Question No:5(a)
Answer:
Attempt at finding PE lost
\(\mathrm{PE}\) lost \(=35 g(4 \cos 22.5-4 \cos 45)\)
\(\frac{1}{2} \times 35 v^{2}=35 g(4 \cos 22.5-4 \cos 45)\)
Speed \(=4.16 \mathrm{~ms}^{-1}(4.1643 \ldots)\)
\(\mathrm{PE}\) lost \(=35 g(4 \cos 22.5-4 \cos 45)\)
\(\frac{1}{2} \times 35 v^{2}=35 g(4 \cos 22.5-4 \cos 45)\)
Speed \(=4.16 \mathrm{~ms}^{-1}(4.1643 \ldots)\)
Knowledge points:
4.5.2 understand the concepts of gravitational potential energy and kinetic energy, and use appropriate formulae
4.5.3 understand and use the relationship between the change in energy of a system and the work done by the external forces, and use in appropriate cases the principle of conservation of energy Including cases where the motion may not be linear (e.g. a child on a smooth curved ‘slide’), where only overall energy changes need to be considered.
Solution:
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