A lorry of mass $$\(16000 \mathrm{~kg}\)$$ is travelling along a straight horizontal road. The engine of the lorry is working at constant power. The work done by the driving force in $$\(10 \mathrm{~s}\)$$ is $$\(750000 \mathrm{~J}\)$$. There is a constant resistance force acting on the lorry of magnitude $$\(2400 \mathrm{~N}\)$$. Find the acceleration of the lorry at an instant when its speed is $$\(25 \mathrm{~m} \mathrm{~s}^{-1}\)$$. .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... ....................................................................................................................................................
Exam No:9709_m20_qp_42 Year:2020 Question No:1(b)
Answer:
Driving force \(\mathrm{DF}=75000 / 25\)
\([\mathrm{DF}-2400=16000 a]\)
\(a=0.0375 \mathrm{~ms}^{-2}\)
\([\mathrm{DF}-2400=16000 a]\)
\(a=0.0375 \mathrm{~ms}^{-2}\)
Knowledge points:
4.5.4 use the definition of power as the rate at which a force does work, and use the relationship between power, force and velocity for a force acting in the direction of motion Including calculation of (average) power;P = Fv
4.5.5 solve problems involving, for example, the instantaneous acceleration of a car moving on a hill
Solution:
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