A minibus of mass $$$4000 \mathrm{~kg}$$$ is travelling along a straight horizontal road. The resistance to motion is $$$900 \mathrm{~N}$$$ Find the driving force when the acceleration of the minibus is $$$0.5 \mathrm{~m} \mathrm{~s}^{-2}$$$. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................

Mathematics

IGCSE&ALevel

CAIE

Exam No：9709_s20_qp_43 Year：2020 Question No：2(a)

Answer:

$F-900=4000 \times 0.5$
(M1 for use of Newton's second law, 3 terms)
$
F=2900 \mathrm{~N}
$

Knowledge points:

4.5.4 use the definition of power as the rate at which a force does work, and use the relationship between power, force and velocity for a force acting in the direction of motion Including calculation of (average) power;P = Fv

4.5.5 solve problems involving, for example, the instantaneous acceleration of a car moving on a hill

Answer:

Knowledge points:

Solution:

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