A minibus of mass $$\(4000 \mathrm{~kg}\)$$ is travelling along a straight horizontal road. The resistance to motion is $$\(900 \mathrm{~N}\)$$ Find the power required for the minibus to maintain a constant speed of $$\(25 \mathrm{~m} \mathrm{~s}^{-1}\)$$. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................
Exam No：9709_s20_qp_43 Year：2020 Question No：2(b)
Answer:
$
900 \times 25
$
(M1 for use of \(P=F v\) with \(F=\) resistance only)
$
22500 \mathrm{~W} \text { or } 22.5 \mathrm{~kW}
$
900 \times 25
$
(M1 for use of \(P=F v\) with \(F=\) resistance only)
$
22500 \mathrm{~W} \text { or } 22.5 \mathrm{~kW}
$
Knowledge points:
4.5.4 use the definition of power as the rate at which a force does work, and use the relationship between power, force and velocity for a force acting in the direction of motion Including calculation of (average) power;P = Fv
Solution:
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