A particle $$\(P\)$$ is projected vertically upwards with speed $$\(5 \mathrm{~m} \mathrm{~s}^{-1}\)$$ from a point $$\(A\)$$ which is $$\(2.8 \mathrm{~m}\)$$ above horizontal ground. Find the length of time for which $$\(P\)$$ is at a height of more than $$\(3.6 \mathrm{~m}\)$$ above the ground. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................
Exam No：9709_s20_qp_41 Year：2020 Question No：3(b)
Answer:
Use of \(s=u t+1 / 2 a t^{2}\)
\(0.8=5 t-5 t^{2}\)
\(t=0.2\) or \(0.8\)
Length of time \(=0.6 \mathrm{~s}\)
\(0.8=5 t-5 t^{2}\)
\(t=0.2\) or \(0.8\)
Length of time \(=0.6 \mathrm{~s}\)
Knowledge points:
4.2.4 use appropriate formulae for motion with constant acceleration in a straight line. （Questions may involve setting up more than one equation, using information about the motion of different particles.）
Solution:
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