A particle $$\(P\)$$ moves in a straight line. The velocity $$\(v \mathrm{~m} \mathrm{~s}^{-1}\)$$ at time $$\(t \mathrm{~s}\)$$ is given by $$\[ \begin{array}{ll} v=2 t+1 & \text { for } 0 \leqslant t \leqslant 5, \\ v=36-t^{2} & \text { for } 5 \leqslant t \leqslant 7, \\ v=2 t-27 & \text { for } 7 \leqslant t \leqslant 13.5 . \end{array} \]$$ Sketch the velocity-time graph for $$\(0 \leqslant t \leqslant 13.5\)$$.

Mathematics
IGCSE&ALevel
CAIE
Exam No:9709_s20_qp_42 Year:2020 Question No:6(a)

Answer:

Correct for \(0 \leq t \leq 5\)
Correct for \(5 \leq t \leq 7\)
Correct for \(7 \leq t \leq 13.5\)

Knowledge points:

4.2.2.1 the area under a velocity–time graph represents displacement
4.2.2.2 the gradient of a displacement–time graph represents velocity
4.2.2.3 the gradient of a velocity–time graph represents acceleration

Solution:

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