A tram starts from rest and moves with uniform acceleration for $$\(20 \mathrm{~s}\)$$. The tram then travels at a constant speed, $$\(V \mathrm{~m} \mathrm{~s}^{-1}\)$$, for $$\(170 \mathrm{~s}\)$$ before being brought to rest with a uniform deceleration of magnitude twice that of the acceleration. The total distance travelled by the tram is $$\(2.775 \mathrm{~km}\)$$. Sketch a velocity-time graph for the motion, stating the total time for which the tram is moving.

Mathematics
IGCSE&ALevel
CAIE
Exam No:9709_s20_qp_42 Year:2020 Question No:1(a)

Answer:

Trapezium, deceleration steeper than acceleration
Time from 0 to 200

Knowledge points:

4.2.2.1 the area under a velocity–time graph represents displacement
4.2.2.2 the gradient of a displacement–time graph represents velocity
4.2.2.3 the gradient of a velocity–time graph represents acceleration

Solution:

Download APP for more features
1. Tons of answers.
2. Smarter Al tools enhance your learning journey.
IOS
Download
Android
Download
Google Play
Download