A tram starts from rest and moves with uniform acceleration for $$\(20 \mathrm{~s}\)$$. The tram then travels at a constant speed, $$\(V \mathrm{~m} \mathrm{~s}^{-1}\)$$, for $$\(170 \mathrm{~s}\)$$ before being brought to rest with a uniform deceleration of magnitude twice that of the acceleration. The total distance travelled by the tram is $$\(2.775 \mathrm{~km}\)$$. Find the magnitude of the acceleration. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................
Exam No:9709_s20_qp_42 Year:2020 Question No:1(c)
Answer:
\(a=15 \div 20\)
\(a=0.75\)
\(a=0.75\)
Knowledge points:
4.2.1 understand the concepts of distance and speed as scalar quantities, and of displacement, velocity and acceleration as vector quantities Restricted to motion in one dimension only. The term ‘deceleration’ may sometimes be used in the context of decreasing speed.
Solution:
Download APP for more features
1. Tons of answers.
2. Smarter Al tools enhance your learning journey.
IOS
Download
Download
Android
Download
Download
Google Play
Download
Download