Accidents at two factories occur randomly and independently. On average, the numbers of accidents per month are $$\(3.1\)$$ at factory $$\(A\)$$ and $$\(1.7\)$$ at factory $$\(B\)$$. Find the probability that the total number of accidents in the two factories during a 2-month period is more than 3. ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................
Exam No:9709_s21_qp_61 Year:2021 Question No:1
Answer:
\(\lambda=(3.1+1.7) \times 2\)
\(=9.6\)
\(1-\mathrm{e}^{-9.6}\left(1+9.6+\frac{9.6^{2}}{2}+\frac{9.6^{3}}{3 !}\right)\)
\(=0.986(3 \mathrm{sf})\)
\(=9.6\)
\(1-\mathrm{e}^{-9.6}\left(1+9.6+\frac{9.6^{2}}{2}+\frac{9.6^{3}}{3 !}\right)\)
\(=0.986(3 \mathrm{sf})\)
Knowledge points:
6.1.1 use formulae to calculate probabilities for the distribution $\text { Po }(\lambda)$
6.2.1.6 if and have independent Poisson distributions then X + Y has a Poisson distribution. (Proofs of these results are not required.)
Solution:
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