An ordinary fair die is thrown repeatedly until a 1 or a 6 is obtained. On another occasion, this die is thrown 3 times. The random variable $$\(X\)$$ is the number of times that a 1 or a 6 is obtained. Find $$\(\mathrm{E}(X)\)$$. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................

Mathematics
IGCSE&ALevel
CAIE
Exam No:9709_m20_qp_52 Year:2020 Question No:2(c)

Answer:

\(\mathrm{E}(X)=\left[0 \times \frac{8}{27}\right]+1 \times \frac{12}{27}+2 \times \frac{6}{27}+3 \times \frac{1}{27}\)
\(=\left[\frac{0}{27}\right]+\frac{12}{27}+\frac{12}{27}+\frac{3}{27}\)
\(=1\)

Knowledge points:

5.4.1 draw up a probability distribution table relating to a given situation involving a discrete random variable X, and calculate E(X) and Var(X)

Solution:

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