Customers arrive at a particular shop at random times. It has been found that the mean number of customers who arrive during a 5-minute interval is $$\(2.1\)$$. Find the probability that at least 4 customers arrive during a 20-minute interval. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................
Exam No：9709_s21_qp_62 Year：2021 Question No：7(b)
Answer:
\(1-\mathrm{e}^{-8.4}\left(1+8.4+\frac{8.4^{2}}{2}+\frac{8.4^{3}}{3 !}\right)\)
\(0.968\) (3 sf)
\(0.968\) (3 sf)
Knowledge points:
6.1.1 use formulae to calculate probabilities for the distribution $\text { Po }(\lambda)$
Solution:
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