$$\(\quad \overrightarrow{A B}=\left(\begin{array}{r}6 \\ -1\end{array}\right) \quad \overrightarrow{B C}=\left(\begin{array}{r}-2 \\ 5\end{array}\right) \quad \overrightarrow{D C}=\left(\begin{array}{r}2 \\ -3\end{array}\right)\)$$ Find $$\(\overrightarrow{B D}\)$$, $$\[ \overrightarrow{B D}=() \]$$
Exam No：0580_w20_qp_43 Year：2020 Question No：8(a)(ii)
Answer:
\(\left(\begin{array}{c}-4 \\ 8\end{array}\right)\)
Knowledge points:
E7.3.2 Represent vectors by directed line segments. (In their answers to questions, candidates are expected to indicate a in some definite way
E7.3.3 Use the sum and difference of two vectors to express given vectors in terms of two coplanar vectors.
E7.3.4 Use position vectors.
Solution:
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