$$\(14 \mathrm{f}(x)=3 x-4 \quad \mathrm{~g}(x)=4 x+1\)$$ $$\(\quad \mathrm{fg}(x)=a x+b\)$$ Find the value of $$\(a\)$$, and the value of $$\(b\)$$. $$\(a=\)$$ $$\(b=\)$$ ...............

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