For the curve shown in the diagram, the normal to the curve at the point $$\(P\)$$ with coordinates $$\((x, y)\)$$ meets the $$\(x\)$$-axis at $$\(N\)$$. The point $$\(M\)$$ is the foot of the perpendicular from $$\(P\)$$ to the $$\(x\)$$-axis. The curve is such that for all values of $$\(x\)$$ in the interval $$\(0 \leqslant x<\frac{1}{2} \pi\)$$, the area of triangle $$\(P M N\)$$ is equal to $$\(\tan x\)$$. Show that $$\(\frac{M N}{y}=\frac{\mathrm{d} y}{\mathrm{~d} x}\)$$. ................................................................................................................................................ ................................................................................................................................................ ................................................................................................................................................ ................................................................................................................................................ ................................................................................................................................................

Mathematics
IGCSE&ALevel
CAIE
Exam No:9709_s21_qp_33 Year:2021 Question No:7(i)

Answer:

Justify the given statement \(\frac{M N}{y}=\frac{\mathrm{d} y}{\mathrm{~d} x}\)

Knowledge points:

1.7.1 understand the gradient of a curve at a point as the limit of the gradients of a suitable sequence of chords, and use the notations for first and second derivatives (Only an informal understanding of the idea of a limit is expected.)

Solution:

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