Georgie has a red scarf, a blue scarf and a yellow scarf. Each day she wears exactly one of these scarves. The probabilities for the three colours are $$\(0.2,0.45\)$$ and $$\(0.35\)$$ respectively. When she wears a red scarf, she always wears a hat. When she wears a blue scarf, she wears a hat with probability $$\(0.4\)$$.When she wears a yellow scarf, she wears a hat with probability $$\(0.3\)$$. Find the probability that on a randomly chosen day Georgie wears a yellow scarf given that she does not wear a hat. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................

Mathematics
IGCSE&ALevel
CAIE
Exam No:9709_m21_qp_52 Year:2021 Question No:2(b)

Answer:

\(P(Y \mid \bar{H})=\frac{P(Y \cap \bar{H})}{P(\bar{H})}=\frac{0.35 \times 0.7}{1-\text { their }(\mathbf{a})}=\frac{0.245}{0.515}\)
\(0.476\) or \(\frac{49}{103}\)

Knowledge points:

5.3.4 calculate and use conditional probabilities in simple cases.

Solution:

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