Here are another three parcels. The total weight of the three parcels is $$\(9.45 \mathrm{~kg}\)$$. Each of the two parcels labelled $$\(D\)$$ have the same weight. The weight of each parcel labelled $$\(D\)$$ is $$\(3 \times\)$$ the weight of the parcel labelled $$\(C\)$$. (b) Work out the weight of the parcel labelled $$\(C\)$$. $$\(\mathrm{kg}\)$$ (2)

Answer:

Knowledge points:

Solution: