If $$\(21^{100}\)$$ has $$\(101^{2}\)$$ positive divisors, how many does $$\(25 \times 21^{100}\)$$ have?
A.
\(2 \times 101^{2}\)
B.
\(3 \times 101^{2}\)
C.
\(5 \times 101^{2}\)
D.
\(25 \times 101^{2}\)
Exam No：2021 First Round Grade 7 Year：2021 Question No：23
Answer:
B
Knowledge points:
G7 - Number Theory - Counting Divisors
Solution:
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