If $$\(x\)$$ is real, $$\(\sqrt{2-\sqrt{2+x}}=x\)$$, then the only possible value of $$\(x\)$$ is.

A.
1
B.
\(\frac{\sqrt{2}}{2}\)
C.
\(\frac{\sqrt{3}-1}{2}\)
D.
\(\frac{\sqrt{5}-1}{2}\)
Mathematics
Competition
Math League
Exam No:2019 First Round Grades 10-12 Year:2019 Question No:21

Answer:

D

Knowledge points:

G10-12 - Algebra - Radical Equations

Solution:

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