In a game, Jim throws three darts at a board. This is called a 'turn'. The centre of the board is called the bull's-eye. The random variable $$\(X\)$$ is the number of darts in a turn that hit the bull's-eye. The probability distribution of $$\(X\)$$ is given in the following table. It is given that $$\(\mathrm{E}(X)=0.55\)$$. Find $$\(\operatorname{Var}(X)\)$$. .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... ....................................................................................................................................................
Exam No:9709_w21_qp_53 Year:2021 Question No:6(b)
Answer:
\(\operatorname{Var}(X)=\) their \(0.3+4 \times\) their \(0.05+9 \times 0.05-0.55^{2}\)
\(0.6475\left[\frac{259}{400}\right]\)
\(0.6475\left[\frac{259}{400}\right]\)
Knowledge points:
5.4.1 draw up a probability distribution table relating to a given situation involving a discrete random variable X, and calculate E(X) and Var(X)
Solution:
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