It is given that $$\(\int_{0}^{a}\left(\frac{4}{2 x+1}+8 x\right) \mathrm{d} x=10\)$$, where $$\(a\)$$ is a positive constant. Using the equation in part (a), show by calculation that 1 < a < 2. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................

Mathematics
IGCSE&ALevel
CAIE
Exam No:9709_s20_qp_23 Year:2020 Question No:7(b)

Answer:

Consider sign of \(a-\sqrt{2.5-0.5 \ln (2 a+1)}\) or equivalent for 1 and 2
Obtain \(-0.3 \ldots\) and \(0.6 \ldots\) or equivalents and justify conclusion

Knowledge points:

2.6.1 locate approximately a root of an equation, by means of graphical considerations and/or searching for a sign change

Solution:

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