Particles $$\(P\)$$ of mass $$\(m \mathrm{~kg}\)$$ and $$\(Q\)$$ of mass $$\(0.2 \mathrm{~kg}\)$$ are free to move on a smooth horizontal plane. $$\(P\)$$ is projected at a speed of $$\(2 \mathrm{~m} \mathrm{~s}^{-1}\)$$ towards $$\(Q\)$$ which is stationary. After the collision $$\(P\)$$ and $$\(Q\)$$ move in opposite directions with speeds of $$\(0.5 \mathrm{~m} \mathrm{~s}^{-1}\)$$ and $$\(1 \mathrm{~m} \mathrm{~s}^{-1}\)$$ respectively. Find $$\(m\)$$. ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................
Exam No:9709_s20_qp_43 Year:2020 Question No:1
Answer:
Use of conservation of momentum
$
m \times 2+0=m \times(-0.5)+0.2 \times 1
$
$
m=0.08
$
$
m \times 2+0=m \times(-0.5)+0.2 \times 1
$
$
m=0.08
$
Knowledge points:
4.3.2 use conservation of linear momentum to solve problems that may be modelled as the direct impact of two bodies. (Including direct impact of two bodies where the bodies coalesce on impact. Knowledge of impulse and the coefficient of restitution is not required.)
Solution:
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