Show that $$\(\frac{\sin \theta}{1-\sin \theta}-\frac{\sin \theta}{1+\sin \theta} \equiv 2 \tan ^{2} \theta\)$$. Hence solve the equation $$\(\frac{\sin \theta}{1-\sin \theta}-\frac{\sin \theta}{1+\sin \theta}=8\)$$, for $$\(0^{\circ}< \theta< 180^{\circ}\)$$. .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... ....................................................................................................................................................

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