Solve the equation $$\(2 \sin \left(\theta+30^{\circ}\right)+5 \cos \theta=2 \sin \theta\)$$ for $$\(0^{\circ}<\theta<90^{\circ}\)$$. ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................
Exam No：9709_m20_qp_22 Year：2020 Question No：1
Answer:
Express first term as \(2 \sin \theta \cos 30+2 \cos \theta \sin 30\)
Divide by \(\cos \theta\) to produce linear equation in \(\tan \theta\) Obtain \(\tan
\theta=\frac{6}{2-\sqrt{3}}\) or \(22.39 \ldots\)
Obtain \(87.4\)
Divide by \(\cos \theta\) to produce linear equation in \(\tan \theta\) Obtain \(\tan
\theta=\frac{6}{2-\sqrt{3}}\) or \(22.39 \ldots\)
Obtain \(87.4\)
Knowledge points:
1.5.4 use the identities
2.3.2.2 the expansions of
Solution:
Download APP for more features
1. Tons of answers.
2. Smarter Al tools enhance your learning journey.
IOS
Download
Download
Android
Download
Download
Google Play
Download
Download