Solve the equation $$\(3 \tan ^{2} \theta+1=\frac{2}{\tan ^{2} \theta}\)$$ for $$\(0^{\circ}<\theta<180^{\circ}\)$$. ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................
Exam No：9709_w20_qp_13 Year：2020 Question No：3
Answer:
\(3 \tan ^{4} \theta+\tan ^{2} \theta-2(=0)\)
\(\left(3 \tan ^{2} \theta-2\right)\left(\tan ^{2} \theta+1\right)(=0)\)
\(\tan \theta=(\pm) \sqrt{\frac{2}{3}}\) or \((\pm) 0.816\) or \((\pm) 0.817\)
\(39.2^{\circ}, 140.8^{\circ}\)
\(\left(3 \tan ^{2} \theta-2\right)\left(\tan ^{2} \theta+1\right)(=0)\)
\(\tan \theta=(\pm) \sqrt{\frac{2}{3}}\) or \((\pm) 0.816\) or \((\pm) 0.817\)
\(39.2^{\circ}, 140.8^{\circ}\)
Knowledge points:
1.1.5 recognise and solve equations in which are quadratic in some function of
1.5.5 find all the solutions of simple trigonometrical equations lying in a specified interval (general forms of solution are not included).
Solution:
Download APP for more features
1. Tons of answers.
2. Smarter Al tools enhance your learning journey.
IOS
Download
Download
Android
Download
Download
Google Play
Download
Download