The diagram shows a ring of mass $$\(0.1 \mathrm{~kg}\)$$ threaded on a fixed horizontal rod. The rod is rough and the coefficient of friction between the ring and the rod is $$\(0.8\)$$. A force of magnitude $$\(T \mathrm{~N}\)$$ acts on the ring in a direction at $$\(30^{\circ}\)$$ to the rod, downwards in the vertical plane containing the rod. Initially the ring is at rest. Find the acceleration of the ring when $$\(T=3\)$$. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................
Exam No：9709_s20_qp_41 Year：2020 Question No：4(b)
Answer:
\(R=3 \sin 30+0.1 g\)
\(3 \cos 30-0.8(3 \sin 30+0.1 g)=0.1 a\)
\(a=5.98 \mathrm{~ms}^{-2}(5.9807 \ldots)\)
\(3 \cos 30-0.8(3 \sin 30+0.1 g)=0.1 a\)
\(a=5.98 \mathrm{~ms}^{-2}(5.9807 \ldots)\)
Knowledge points:
4.4.1 apply Newton’s laws of motion to the linear motion of a particle of constant mass moving under the action of constant forces, which may include friction, tension in an inextensible string and thrust in a connecting rod If any other forces resisting motion are to be considered (e.g. air resistance) this will be indicated in the question.
Solution:
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