The diagram shows a sector $$\(O X Y\)$$ of a circle with centre $$\(O\)$$ and radius $$\(9.5 \mathrm{~cm}\)$$. The sector angle is $$\(53^{\circ}\)$$. $$\(A\)$$ lies on $$\(O X, B\)$$ lies on $$\(O Y\)$$ and $$\(O A=O B\)$$. The area of triangle $$\(O A B\)$$ is $$\(\frac{1}{3}\)$$ of the area of sector $$\(O X Y\)$$. Calculate $$\(O A\)$$. $$\(OA=\)$$ ....................................... $$\(\mathrm{cm}\)$$
Exam No:0580_m21_qp_42 Year:2021 Question No:8(a)(ii)
Answer:
\(5.9[0]\) or \(5.899\) to \(5.903\)..
Knowledge points:
E5.2 Carry out calculations involving the perimeter and area of a rectangle, triangle, parallelogram and trapezium and compound shapes derived from these.
E6.4 Solve problems using sine and cosine rules and the area formula for triangles.
Solution:
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