The diagram shows a quadrilateral $$\(A B C D\)$$ made from two triangles, $$\(A B D\)$$ and $$\(B C D\)$$. Show that $$\(B D=16.9 \mathrm{~m}\)$$, correct to 1 decimal place.
Exam No：0580_s21_qp_42 Year：2021 Question No：6(a)
Answer:
\(\sqrt{16^{2}+19^{2}-2 \times 16 \times 19 \cos 57}\) oe
\(16.90\) to \(16.91\)
\(16.90\) to \(16.91\)
Knowledge points:
E6.4 Solve problems using sine and cosine rules and the area formula for triangles.
Solution:
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