The diagram shows a frustum of a cone and a sphere. The frustum is made by removing a small cone from a large cone. The cones are similar. The height of the small cone is $$\(h \mathrm{~cm}\)$$. The height of the large cone is $$\(2 h \mathrm{~cm}\)$$. The radius of the base of the large cone is $$\(r \mathrm{~cm}\)$$. The radius of the sphere is $$\(r \mathrm{~cm}\)$$. Given that the volume of the frustum is equal to the volume of the sphere, find an expression for $$\(r\)$$ in terms of $$\(h\)$$. Give your expression in its simplest form. $$\[ r=. \]$$
Exam No:4MA1_1HR_que_20200305 Year:2020 Question No:20
Answer:
Knowledge points:
2: Equations, formulae and identities
Solution:
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