The diagram shows part of the curve $$$y=\frac{2}{(3-2 x)^{2}}-x$$$ and its minimum point $$$M$$$, which lies on the $$$x$$$-axis. Find the area of the shaded region bounded by the curve and the coordinate axes. .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... ....................................................................................................................................................

Mathematics

IGCSE&ALevel

CAIE

Exam No：9709_w20_qp_12 Year：2020 Question No：10(c)

Answer:

Area under curve $=$ their $\left[\frac{1}{3-2 \times\left(\frac{1}{2}\right)}-\frac{\left(\frac{1}{2}\right)^{2}}{2}\right]-\left[\frac{1}{3-2 \times 0}-0\right]$
$\frac{1}{24}$

Knowledge points:

1.8.3 evaluate definite integrals (Including simple cases of ‘improper’ integrals, such as)

1.8.4.1 the area of a region bounded by a curve and lines parallel to the axes, or between a curve and a line or between two curves

Answer:

Knowledge points:

Solution:

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