The diagram shows the speed-time graph for the final 40 seconds of a car journey. At the start of the 40 seconds the speed is $$\(v \mathrm{~m} / \mathrm{s}\)$$. The total distance travelled during the 40 seconds is $$\(1.24\)$$ kilometres. Find the value of $$\(v\)$$. $$\[ v=........................... \]$$
Exam No:0580_w20_qp_23 Year:2020 Question No:19(b)
Answer:
\(32.5\)
Knowledge points:
E2.10.1 Interpret and use graphs in practical situations including travel graphs and conversion graphs.
E2.10.2 Draw graphs from given data.
E2.10.3 Apply the idea of rate of change to simple kinematics involving distance–time and speed–time graphs, acceleration and deceleration. (May include estimation and interpretation of the gradient of a tangent at a point.)
E2.10.4 Calculate distance travelled as area under a speed–time graph.
E2.5.1 Derive and solve linear equations in one unknown
E2.5.2 Derive and solve simultaneous linear equations in two unknowns.
E2.5.3 Derive and solve simultaneous equations, involving one linear and one quadratic.
E2.5.4 Derive and solve quadratic equations by factorisation, completing the square and by use of the formula.
E2.5.5 Derive and solve linear inequalities. (Including representing and interpreting inequalities on a number line.) (Interpretation of results may be required.)
E5.1 Use current units of mass, length, area, volume and capacity in practical situations and express quantities in terms of larger or smaller units. (Convert between units including units of area and volume.)
Solution:
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