The diagram shows the curve with parametric equations $$\[ x=4 t+\mathrm{e}^{2 t}, \quad y=6 t \sin 2 t, \]$$ for $$\(0 \leqslant t \leqslant 1\)$$. The point $$\(P\)$$ on the curve has parameter $$\(p\)$$ and $$\(y\)$$-coordinate 3 . Show that $$\(p=\frac{1}{2 \sin 2 p}\)$$. .................................................................................................................................................... .................................................................................................................................................... ....................................................................................................................................................

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