The equation of a curve is $$$2 \mathrm{e}^{2 x} y-y^{3}+4=0$$$. Show that the curve has no stationary points. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................

Mathematics

IGCSE&ALevel

CAIE

Exam No：9709_w20_qp_22 Year：2020 Question No：5(c)

Answer:

Equate numerator of derivative to zero and state that at least one of $\mathrm{e}^{2 x}$ and $y$ cannot be zero
Complete argument

Knowledge points:

1.7.3 apply differentiation to gradients, tangents and normals, increasing and decreasing functions and rates of change (Including connected rates of change, e.g. given the rate of increase of the radius of a circle, find the rate of increase of the area for a specific value of one of the variables.)

Answer:

Knowledge points:

Solution:

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