The equation of a circle is $$\(x^{2}+y^{2}+p x+2 y+q=0\)$$, where $$\(p\)$$ and $$\(q\)$$ are constants. Express the equation in the form $$\((x-a)^{2}+(y-b)^{2}=r^{2}\)$$, where $$\(a\)$$ is to be given in terms of $$\(p\)$$ and $$\(r^{2}\)$$ is to be given in terms of $$\(p\)$$ and $$\(q\)$$. ........................................................................................................................................................ . ........................................................................................................................................................ . ........................................................................................................................................................ . ........................................................................................................................................................ . ........................................................................................................................................................ . ........................................................................................................................................................ . ........................................................................................................................................................ . The line with equation $$\(x+2 y=10\)$$ is the tangent to the circle at the point $$\(A(4,3)\)$$.
Exam No:9709_w24_qp_12 Year:2024 Question No:8(a)
Answer:

Knowledge points:
1.3.3 understand that the equation represents the circle with centre and radius (Including use of the expanded form.)
1.3.4 use algebraic methods to solve problems involving lines and circles (Including use of elementary geometrical properties of circles, e.g. tangent perpendicular to radius, angle in a semicircle, symmetry.) (Implicit differentiation is not included.)
Solution:
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