The graph of the probability density function of a random variable $$\(X\)$$ is symmetrical about the line $$\(x=4\)$$. Given that $$\(\mathrm{P}(X<5)=\frac{20}{27}\)$$, find P(3<X<5)
Exam No:9709_s21_qp_61 Year:2021 Question No:3
Answer:
\( \begin{array}{l}
1-\frac{20}{27} \text { or } \frac{20}{27}-\frac{1}{2} \\ \frac{20}{27}-\left(1-\frac{20}{27}\right) \text { or }\left(\frac{20}{27}-\frac{1}{2}\right)
\end{array} \)
\(\frac{13}{27}\)
1-\frac{20}{27} \text { or } \frac{20}{27}-\frac{1}{2} \\ \frac{20}{27}-\left(1-\frac{20}{27}\right) \text { or }\left(\frac{20}{27}-\frac{1}{2}\right)
\end{array} \)
\(\frac{13}{27}\)
Knowledge points:
6.3.1 understand the concept of a continuous random variable, and recall and use properties of a probability density function (For density functions defined over a single interval only; the domain may be infinite,.)
6.3.2 use a probability density function to solve problems involving probabilities, and to calculate the mean and variance of a distribution. (Including location of the median or other percentiles of a distribution by direct consideration of an area using the density function.) (Explicit knowledge of the cumulative distribution function is not included.)
Solution:
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