The polynomial $$\(\mathrm{p}(x)\)$$ is defined by $$\( \mathrm{p}(x)=6 x^{3}+a x^{2}-4 x-3 \)$$ where $$\(a\)$$ is a constant. It is given that $$\((x+3)\)$$ is a factor of $$\(\mathrm{p}(x)\)$$. Using this value of $$\(a\)$$, factorise $$\(\mathrm{p}(x)\)$$ completely. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................
Exam No:9709_s20_qp_22 Year:2020 Question No:6(b)
Answer:
Divide by \(x+3\) at least as far as the \(x\) term
Obtain \(6 x^{2}-x-1\)
Conclude \((x+3)(3 x+1)(2 x-1)\)
Obtain \(6 x^{2}-x-1\)
Conclude \((x+3)(3 x+1)(2 x-1)\)
Knowledge points:
2.1.3 use the factor theorem and the remainder theorem.
Solution:
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