The polynomial $$\(\mathrm{p}(x)\)$$ is defined by $$\( \mathrm{p}(x)=6 x^{3}+a x^{2}-4 x-3 \)$$ where $$\(a\)$$ is a constant. It is given that $$\((x+3)\)$$ is a factor of $$\(\mathrm{p}(x)\)$$. Find the value of $$\(a\)$$. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................

Mathematics
IGCSE&ALevel
CAIE
Exam No:9709_s20_qp_23 Year:2020 Question No:6(a)

Answer:

Substitute \(x=-3\), equate to zero and attempt solution for \(a\)
Obtain \(a=17\)

Knowledge points:

2.1.3 use the factor theorem and the remainder theorem.

Solution:

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