The probability that a student at a large music college plays in the band is $$\(0.6\)$$. For a student who plays in the band, the probability that she also sings in the choir is $$\(0.3\)$$. For a student who does not play in the band, the probability that she sings in the choir is $$\(x\)$$. The probability that a randomly chosen student from the college does not sing in the choir is $$\(0.58\)$$. Two students from the college are chosen at random. Find the probability that both students play in the band and both sing in the choir. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................

Mathematics
IGCSE&ALevel
CAIE
Exam No:9709_w20_qp_51 Year:2020 Question No:2(b)

Answer:

\((0.6 \times 0.3)^{2}\)
\(0.0324\)

Knowledge points:

5.3.2 use addition and multiplication of probabilities, as appropriate, in simple cases (Explicit use of the general formula is not required.)

Solution:

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