The product of the remainders from dividing my secret number by 2 , by 3 , by 4 , and by 5 is greater than 0 . My secret number could be

A.
\(5 \times 7 \times 11\)
B.
\(7 \times 8 \times 9\)
C.
\(7 \times 9 \times 11\)
D.
\(7 \times 11 \times 13\)
Mathematics
Competition
Math League
Exam No:2022 First Round Grade 5 Year:2022 Question No:15

Answer:

D

Knowledge points:

G5 - Number Theory - Division with Remainder (Cyclical Patterns)

Solution:

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