The table shows some values for $$\(y=2 \times 0.5^{x}-1\)$$. By drawing a suitable straight line, solve the equation $$\(2 \times 0.5^{x}+2 x-3.5=0\)$$ for $$\(-1 \leqslant x \leqslant 2\)$$. $$\[ x=................................... \]$$
Exam No：0580_s21_qp_42 Year：2021 Question No：2(b)
Answer:
\(
y=2.5-2 x \text { ruled }
\)
\(1.3\) to \(1.4\)
y=2.5-2 x \text { ruled }
\)
\(1.3\) to \(1.4\)
Knowledge points:
E2.11.1
E2.11.2 Solve associated equations approximately, including finding and interpreting roots by graphical methods. (Find turning points of quadratics by completing the square.)
E2.11.3 Draw and interpret graphs representing exponential growth and decay problems.
E2.11.4 Recognise, sketch and interpret graphs of functions. (Linear, quadratic, cubic, reciprocal and exponential.) (Knowledge of turning points and asymptotes is required.)
Solution:
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